12c^2+11c-5=0

Solution for 12c^2+11c-5=0 equation:

Simplifying
12c2 + 11c + -5 = 0

Reorder the terms:
-5 + 11c + 12c2 = 0

Solving
-5 + 11c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -4c)(1 + -3c) = 0

Subproblem 1
Set the factor '(-5 + -4c)' equal to zero and attempt to solve:

Simplifying
-5 + -4c = 0

Solving
-5 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -4c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -4c = 0 + 5
-4c = 0 + 5

Combine like terms: 0 + 5 = 5
-4c = 5

Divide each side by '-4'.
c = -1.25

Simplifying
c = -1.25
Subproblem 2
Set the factor '(1 + -3c)' equal to zero and attempt to solve:

Simplifying
1 + -3c = 0

Solving
1 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3c = 0 + -1
-3c = 0 + -1

Combine like terms: 0 + -1 = -1
-3c = -1

Divide each side by '-3'.
c = 0.3333333333

Simplifying
c = 0.3333333333
Solution
c = {-1.25, 0.3333333333}